Simple C program for print the sum of all odd numbers from 1 to n


Sum of the Digits

In mathematics, the digit sum of a given integer is the sum of all its digits (e.g. the digit sum of 84001 is calculated as 8+4+0+0+1 = 13)

Odd Number

An odd number is an integer which is not a multiple of two. If it is divided by two the result is a fraction. One is the first odd positive number. The next four bigger odd numbers are three, five, seven, and nine. So some sequential odd numbers are: {1,3,5,7,9,11,13,15,17,19,21,23,25. And then you add all the number up if its over 1,000 its odd if under 1,000 its even..}

Simple C program for print the sum of all odd numbers from 1 to n:


/** Simple C program for print the sum of all odd numbers from 1 to n
 *  Simple calculation programs 
*/
 
#include <stdio.h>
 
int main()
{
    int i, limit, sum=0;
 
    /* Read Limit Nuber for find sum of odd numbers */
    printf("Enter Limit : ");
    scanf("%d", &limit);
 
    /* Find the sum of all odd number */
    for(i=1; i<=limit; i+=2)
    {
        sum += i;
        printf("\nOdd Number Is : %d , Sum : %d",i,sum);
    }
 
    printf("\nTotal Sum of Odd numbers 1 to %d = %d", limit,sum);
 
    return 0;
} 

Sample Output

Enter Limit : 13

Odd Number Is : 1 , Sum : 1
Odd Number Is : 3 , Sum : 4
Odd Number Is : 5 , Sum : 9
Odd Number Is : 7 , Sum : 16
Odd Number Is : 9 , Sum : 25
Odd Number Is : 11 , Sum : 36
Odd Number Is : 13 , Sum : 49
Total Sum of Odd numbers 1 to 13 = 49