Simple Program for Change the Value of Constant Integer using...

About this program

This is an example program in c pointer example programs. Read the concept first: C Pointers, then study the code and output below.

Poniter Syntax:

pointer_vaibale = &variable;

Simple Program for Change the value of constant integer Using Pointer

/* Simple Program for Change the value of constant integer Using Pointer in C*/
/* Print Pointer Address Program,C Pointer Examples */

#include <stdio.h>

int main() {
  const int a = 100;
  int *pt;

  printf("Pointer Example Program : Change the value of constant integer\n");

  pt = &a;
  *pt = 200;

  printf("\n[a  ]:Value of A = %d", a);

  return 0;
}

/*
 * But It throws warning in GCC compiler
 * change_const.c:12:6: warning: assignment discards 'const' 
 * qualifier from pointer target type [-Wdiscarded-qualifiers]
 * */

Sample Output:

Pointer Example Program : Change the value of constant integer

[a  ]:Value of A = 200

How It Works

This C program demonstrates Simple Program for Change the Value of Constant Integer using… It first prepares the data it needs, then performs the core operation step by step, and finally prints the output shown in the Sample Output above.

1. Declare the variables that hold the program’s data.
2. Print the final result to the console so you can compare it with the sample output.

Try changing the input values and re-running the program to see how the output changes — this is the fastest way to understand how the logic behaves.

Related Pages

Learn the concept first, then study the code:

• C Programs — Browse all C Programs.
• C Pointers — Concept — pointers, addresses and dereferencing.
• Simple Pointer Example Program — More in c pointer example programs.
• Simple Program for Print address of Variable Using Pointer in C — More in c pointer example programs.